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#1
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copy first line in a cell
I have an address
Any place Anywhere UK in the above format. I want to be be to copy the first line into another cell. I have found first word but some places have 2 names or even 3. Can anyone help? I need to do this with a formula and not vba. thanks Nev |
#2
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Answer: copy first line in a cell
Extracting the First Line of an Address in Excel
Assuming your address is in cell A1, follow these steps: [list=1][*]Use the FIND function to find the position of the first line break character. The formula would be: Code:
=FIND(CHAR(10),A1) [*]Use the LEFT function to extract the first line of the address. The formula would be: Code:
=LEFT(A1,FIND(CHAR(10),A1)-1) Note that the CHAR(10) function is used to represent the line break character in the formula.
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#3
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copy first line in a cell
One way =LEFT(D19,FIND(" ",D19,FIND(" ",D19)+1)-FIND(" ",D19)) -- Don Guillett Microsoft MVP Excel SalesAid Software "Nev" wrote in message ... I have an address Any place Anywhere UK in the above format. I want to be be to copy the first line into another cell. I have found first word but some places have 2 names or even 3. Can anyone help? I need to do this with a formula and not vba. thanks Nev |
#4
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copy first line in a cell
On Sat, 23 May 2009 05:26:01 -0700, Nev wrote:
I have an address Any place Anywhere UK in the above format. I want to be be to copy the first line into another cell. I have found first word but some places have 2 names or even 3. Can anyone help? I need to do this with a formula and not vba. thanks Nev =LEFT(A1,FIND(CHAR(10),A1)-1) CHAR(10) is the LineFeed character; which should be at the end of the first line. --ron |
#5
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copy first line in a cell
That's great Thanks. If I wanted to get the 1st two line or second line
only, how would that work? Thanks Nev "Ron Rosenfeld" wrote: On Sat, 23 May 2009 05:26:01 -0700, Nev wrote: I have an address Any place Anywhere UK in the above format. I want to be be to copy the first line into another cell. I have found first word but some places have 2 names or even 3. Can anyone help? I need to do this with a formula and not vba. thanks Nev =LEFT(A1,FIND(CHAR(10),A1)-1) CHAR(10) is the LineFeed character; which should be at the end of the first line. --ron |
#6
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copy first line in a cell
On Sun, 24 May 2009 01:57:04 -0700, Nev wrote:
That's great Thanks. If I wanted to get the 1st two line or second line only, how would that work? Thanks Nev Glad to help. For the 1st two lines, you need to look for the second <lf character. The SUBSTITUTE worksheet function allows you to specify the instance of a character. So =SUBSTITUTE(A1,CHAR(10),CHAR(1),2) would substitute a CHAR(1) for the <lf. Then you just look for that: =LEFT(A1,FIND(CHAR(1),SUBSTITUTE(A1,CHAR(10),CHAR( 1),2))-1) To get just the second line, you use the MID function and go from the first <lf to your substituted CHAR(1). So something like: =MID(A1,FIND(CHAR(10),A1)+1,FIND(CHAR(1), SUBSTITUTE(A1,CHAR(10),CHAR(1),2))-FIND(CHAR(10),A1)-1) I find it simpler to use either Longre's free morefunc.xll add-in and the regular expression formula: =REGEX.MID(A1,".+",<LineNumber) for work like this. The .xll will not work on strings longer than 255 characters, in which case I would use a "home grown" VBA routine that does pretty much the same thing. --ron |
#7
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copy first line in a cell
Ron
That's brilliant - i will give it a go Thanks Nev "Ron Rosenfeld" wrote: On Sun, 24 May 2009 01:57:04 -0700, Nev wrote: That's great Thanks. If I wanted to get the 1st two line or second line only, how would that work? Thanks Nev Glad to help. For the 1st two lines, you need to look for the second <lf character. The SUBSTITUTE worksheet function allows you to specify the instance of a character. So =SUBSTITUTE(A1,CHAR(10),CHAR(1),2) would substitute a CHAR(1) for the <lf. Then you just look for that: =LEFT(A1,FIND(CHAR(1),SUBSTITUTE(A1,CHAR(10),CHAR( 1),2))-1) To get just the second line, you use the MID function and go from the first <lf to your substituted CHAR(1). So something like: =MID(A1,FIND(CHAR(10),A1)+1,FIND(CHAR(1), SUBSTITUTE(A1,CHAR(10),CHAR(1),2))-FIND(CHAR(10),A1)-1) I find it simpler to use either Longre's free morefunc.xll add-in and the regular expression formula: =REGEX.MID(A1,".+",<LineNumber) for work like this. The .xll will not work on strings longer than 255 characters, in which case I would use a "home grown" VBA routine that does pretty much the same thing. --ron |
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