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VBA "Find" with multiple criterion



 
 
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  #11  
Old August 15th 12, 03:20 PM
KeriM KeriM is offline
Member
 
First recorded activity by ExcelBanter: Jul 2012
Posts: 57
Default

Quote:
Originally Posted by John Keith View Post
On Mon, 13 Aug 2012 15:48:25 +0000, KeriM
> wrote:

>
>I'm trying to do a somewhat complicated find in VBA.
>
>I have a worksheet with column B having only two different values (eg. a
>and b). Column C has values that repeat for each value for column B.
>(eg. 1 and 2). The values that I want to return are in columns E and F.
>
>
>So what I'm trying to do is this:
>
>If columns B and C equal "a" and "1" (respectively), then subtract the
>values in E and F (on that row where the columns equal) and return that
>result on another worksheet.
>
>Repeat for all the different combinations...a1, a2, b1, b2.
>
>To illustrate:
>
>
>Code:
>--------------------
>
>
> Column B | Column C Column E | Column F
>
> a 1 70 50
> a 2 80 30
> b 1 60 20
> b 2 40 20
>
>
>--------------------
>
>
>I want to find a1 and write "20" in another worksheet.
>
>Sorry if this is an overly long explanation, I feel like it's confusing
>to explain. Let me know if anything needs to be clarified. As always,
>any help is appreciated!


How long is your list? Is the data contiguous? Do you want to store
the result in the same row on the other worksheet?

Setting those questions aside I'd suggest either a FOR/WHILE loop. I
suppose there are more elegant methods and most experts try to avoid
loops but they can be quite fast for a simple operation like this and
the code is easy to understand.

For i = first_row to last_row
if cells(i, "B") = "a" and cells(i, "C") = 1 then _
worksheets(othersheet).cells(i, "A")= cells(i, "E") - cells(i, "F")
Next i

This all assumes I understood your question and there are several
details to check to meet what you really have to work with.

John Keith
John,

You understand what I'm trying to do. To answer your questions:

How long is your list?
401 rows, but that may change (I'd rather not hard-code it)

Is the data contiguous?
Yes

Do you want to store the result in the same row on the other worksheet?
I need to store the results in the same column, but different rows.


Your solution so far makes perfect sense.
I tried modifying this part for my code:

Code:
For i = first_row to last_row
If cells(i, "B") = "a" and cells(i, "C") = 1 Then....
For now, can we just select the row where it finds those two values? I want to see that it works, and I'm not sure how to do that.

I'm also having a problem with what it's supposed to equal to since those values are not the only values in the cells. It doesn't just say "a" in the column I'm searching for. It says something like "a 2342 332" and it doesn't just say "1" in column C, it says "abcdefg (1bb)." Point is, I have more than just the string I'm searching for in the cells. Do you know how I can use wildcards in the search? Thanks, you've been really helpful so far!
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  #12  
Old August 17th 12, 06:42 AM posted to microsoft.public.excel.programming
John Keith
external usenet poster
 
Posts: 172
Default VBA "Find" with multiple criterion

As usual there are many ways to address the next requirements for
testing the cell contents as you describe below. But the simplest
solution I would use would be to test the cell to see if it contains
"a" or "1" by using the instr function like this:

For i = first_row to last_row
if instr(cells(i, "B")',"a")>0 and instr(cells(i, "C"),"1")>0 then _
worksheets(othersheet).cells(i, "A")= cells(i, "E") - cells(i, "F")
Next i

The second line in the loop will store your result in the same row on
the target sheet as the source sheet.

For only 400 lines of data the for loop will be very fast.


On Wed, 15 Aug 2012 14:20:15 +0000, KeriM
> wrote:

>
>John Keith;1604636 Wrote:
>> On Mon, 13 Aug 2012 15:48:25 +0000, KeriM
>> > wrote:
>> -
>> >
>> >I'm trying to do a somewhat complicated find in VBA.
>> >
>> >I have a worksheet with column B having only two different values (eg.

>> a
>> >and b). Column C has values that repeat for each value for column B.
>> >(eg. 1 and 2). The values that I want to return are in columns E and

>> F.
>> >
>> >
>> >So what I'm trying to do is this:
>> >
>> >If columns B and C equal "a" and "1" (respectively), then subtract the
>> >values in E and F (on that row where the columns equal) and return

>> that
>> >result on another worksheet.
>> >
>> >Repeat for all the different combinations...a1, a2, b1, b2.
>> >
>> >To illustrate:
>> >
>> >
>> >Code:
>> >--------------------
>> >
>> >
>> > Column B | Column C Column E | Column F
>> >
>> > a 1 70 50
>> > a 2 80 30
>> > b 1 60 20
>> > b 2 40 20
>> >
>> >
>> >--------------------
>> >
>> >
>> >I want to find a1 and write "20" in another worksheet.
>> >
>> >Sorry if this is an overly long explanation, I feel like it's

>> confusing
>> >to explain. Let me know if anything needs to be clarified. As always,
>> >any help is appreciated!-

>>
>> How long is your list? Is the data contiguous? Do you want to store
>> the result in the same row on the other worksheet?
>>
>> Setting those questions aside I'd suggest either a FOR/WHILE loop. I
>> suppose there are more elegant methods and most experts try to avoid
>> loops but they can be quite fast for a simple operation like this and
>> the code is easy to understand.
>>
>> For i = first_row to last_row
>> if cells(i, "B") = "a" and cells(i, "C") = 1 then _
>> worksheets(othersheet).cells(i, "A")= cells(i, "E") - cells(i, "F")
>> Next i
>>
>> This all assumes I understood your question and there are several
>> details to check to meet what you really have to work with.
>>
>> John Keith
>>

>
>John,
>
>You understand what I'm trying to do. To answer your questions:
>
>How long is your list?
>401 rows, but that may change (I'd rather not hard-code it)
>
>Is the data contiguous?
>Yes
>
>Do you want to store the result in the same row on the other worksheet?
>I need to store the results in the same column, but different rows.
>
>
>
>Your solution so far makes perfect sense.
>I tried modifying this part for my code:
>
>
>Code:
>--------------------
>
>
> For i = first_row to last_row
> If cells(i, "B") = "a" and cells(i, "C") = 1 Then....
>
>
>--------------------
>
>
>For now, can we just select the row where it finds those two values? I
>want to see that it works, and I'm not sure how to do that.
>
>I'm also having a problem with what it's supposed to equal to since
>those values are not the only values in the cells. It doesn't just say
>"a" in the column I'm searching for. It says something like "a 2342 332"
>and it doesn't just say "1" in column C, it says "abcdefg (1bb)." Point
>is, I have more than just the string I'm searching for in the cells. Do
>you know how I can use wildcards in the search? Thanks, you've been
>really helpful so far!


John Keith

  #13  
Old August 17th 12, 09:15 PM
KeriM KeriM is offline
Member
 
First recorded activity by ExcelBanter: Jul 2012
Posts: 57
Default

Quote:
Originally Posted by John Keith View Post
As usual there are many ways to address the next requirements for
testing the cell contents as you describe below. But the simplest
solution I would use would be to test the cell to see if it contains
"a" or "1" by using the instr function like this:

For i = first_row to last_row
if instr(cells(i, "B")',"a")>0 and instr(cells(i, "C"),"1")>0 then _
worksheets(othersheet).cells(i, "A")= cells(i, "E") - cells(i, "F")
Next i

The second line in the loop will store your result in the same row on
the target sheet as the source sheet.

For only 400 lines of data the for loop will be very fast.
John,

Perfect! It does the calculation and writes it on the source worksheet.

Now, how can I get it write to another workbook? This one may be a bit tricker, because the workbook I want to write to doesn't always have the same name (it is always open though). This is how it is written (and working) for my other sheets:

Code:
Dim ws As Workbook
If ws.Name Like "*Count*" Then
Windows(ws.Name).Select
    Range("C3").Select
    ActiveCell.FormulaR1C1 = 'write answer here'
When I tried to implement this code into yours, it was posting a value of 0, probably because it lost the values when I switched sheets. Can I store the answer in a variable and then call the variable to write the answer in the cell?

Last edited by KeriM : August 17th 12 at 09:18 PM. Reason: Added information, shortened quote
  #14  
Old August 17th 12, 09:41 PM
KeriM KeriM is offline
Member
 
First recorded activity by ExcelBanter: Jul 2012
Posts: 57
Default

Quote:
Originally Posted by KeriM View Post
John,

Perfect! It does the calculation and writes it on the source worksheet.

Now, how can I get it write to another workbook? This one may be a bit tricker, because the workbook I want to write to doesn't always have the same name (it is always open though). This is how it is written (and working) for my other sheets:

Code:
Dim ws As Workbook
If ws.Name Like "*Count*" Then
Windows(ws.Name).Select
    Range("C3").Select
    ActiveCell.FormulaR1C1 = 'write answer here'
When I tried to implement this code into yours, it was posting a value of 0, probably because it lost the values when I switched sheets. Can I store the answer in a variable and then call the variable to write the answer in the cell?
Update: tried it again, it works!

Code:
For i = 1 To 700
If InStr(Cells(i, 2), "a") And InStr(Cells(i, 3), "1") Then
num = Cells(i, 5) - Cells(i, 6)
For Each ws In Workbooks
If ws.Name Like "*Count*" Then Windows(ws.Name).Activate
Next
Range("C3").Select
ActiveCell.FormulaR1C1 = num
End If
Next i
Thanks so much for your help John!
  #15  
Old August 18th 12, 03:12 AM posted to microsoft.public.excel.programming
John Keith
external usenet poster
 
Posts: 172
Default VBA "Find" with multiple criterion

>Now, how can I get it write to another workbook? This one may be a bit
>tricker, because the workbook I want to write to doesn't always have the
>same name (it is always open though).


Change this line (to the equal sign):

worksheets(othersheet).cells(i, "A")= cells(i, "E") - cells(i, "F")

to something like:

workbooks(ws.Name).activesheet.ActiveCell.FormulaR 1C1 =

You may need to tweak this a little but basically you need to
reference the workbook, then the worksheet and then the cell.


On Fri, 17 Aug 2012 20:15:09 +0000, KeriM
> wrote:

>
>John Keith;1604696 Wrote:
>> As usual there are many ways to address the next requirements for
>> testing the cell contents as you describe below. But the simplest
>> solution I would use would be to test the cell to see if it contains
>> "a" or "1" by using the instr function like this:
>>
>> For i = first_row to last_row
>> if instr(cells(i, "B")',"a")>0 and instr(cells(i, "C"),"1")>0 then _
>> worksheets(othersheet).cells(i, "A")= cells(i, "E") - cells(i, "F")
>> Next i
>>
>> The second line in the loop will store your result in the same row on
>> the target sheet as the source sheet.
>>
>> For only 400 lines of data the for loop will be very fast.
>>
>>

>
>John,
>
>Perfect! It does the calculation and writes it on the source worksheet.
>
>
>Now, how can I get it write to another workbook? This one may be a bit
>tricker, because the workbook I want to write to doesn't always have the
>same name (it is always open though). This is how it is written (and
>working) for my other sheets:
>
>
>Code:
>--------------------
>
>
> Dim ws As Workbook
> If ws.Name Like "*Count*" Then
> Windows(ws.Name).Select
> Range("C3").Select
> ActiveCell.FormulaR1C1 = 'write answer here'
>
>--------------------
>
>
>When I tried to implement this code into yours, it was posting a value
>of 0, probably because it lost the values when I switched sheets. Can I
>store the answer in a variable and then call the variable to write the
>answer in the cell?


John Keith

  #16  
Old August 20th 12, 06:42 PM
KeriM KeriM is offline
Member
 
First recorded activity by ExcelBanter: Jul 2012
Posts: 57
Default

John,

One more question. How do I get it to loop through all the sets of criteria and put it where I want it to go? For example, I want "a1" to go into cell C3, "a2" to go into cell C4, "b1" to go into cell C8, "b2" to go into cell C9, etc. I can do it with one set of criterion (like "a1"), but how do I combine it with all my criteria?
  #17  
Old August 20th 12, 09:02 PM
KeriM KeriM is offline
Member
 
First recorded activity by ExcelBanter: Jul 2012
Posts: 57
Default

Quote:
Originally Posted by KeriM View Post
John,

One more question. How do I get it to loop through all the sets of criteria and put it where I want it to go? For example, I want "a1" to go into cell C3, "a2" to go into cell C4, "b1" to go into cell C8, "b2" to go into cell C9, etc. I can do it with one set of criterion (like "a1"), but how do I combine it with all my criteria?
I was able to get it working; however, I ended up just putting each set of values in their own sub and making a big runall() at the top so it just runs through all the subs. Is there a more efficient way?
  #18  
Old August 21st 12, 04:32 AM posted to microsoft.public.excel.programming
John Keith
external usenet poster
 
Posts: 172
Default VBA "Find" with multiple criterion

I've lost track of the detail of what you're trying to do at this
point. If you have something that works for you and runs fast enough
don't worry about being more efficient.

On Mon, 20 Aug 2012 20:02:52 +0000, KeriM
> wrote:

>
>KeriM;1604763 Wrote:
>> John,
>>
>> One more question. How do I get it to loop through all the sets of
>> criteria and put it where I want it to go? For example, I want "a1" to
>> go into cell C3, "a2" to go into cell C4, "b1" to go into cell C8, "b2"
>> to go into cell C9, etc. I can do it with one set of criterion (like
>> "a1"), but how do I combine it with all my criteria?

>
>I was able to get it working; however, I ended up just putting each set
>of values in their own sub and making a big runall() at the top so it
>just runs through all the subs. Is there a more efficient way?


John Keith

  #19  
Old August 21st 12, 01:15 PM
KeriM KeriM is offline
Member
 
First recorded activity by ExcelBanter: Jul 2012
Posts: 57
Default

Quote:
Originally Posted by John Keith View Post
I've lost track of the detail of what you're trying to do at this
point. If you have something that works for you and runs fast enough
don't worry about being more efficient.
Ha ha. Fair enough. Thank you so much for your help on this!
 




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