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Arvi Laanemets
 
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Hi


"Dave Peterson" wrote in message
...
I think you dropped some double quotes:

=hyperlink("\\fil-....!K12","myLink")


More exactly, OE somehow did it - at start quotes were there. I'm trying
again - the right formula will be:

=HYPERLINK("\\FIL-NW02-06\MPTTechTeamLeaders\8 Tech Team Scorecard\Reddy
Team Scorecards\2005_Define_Scorecard_Hixon.xls#'Scorec ard - Tech
Group'!K12","MyLink")


Arvi Laanemets




Arvi Laanemets wrote:

Hi

This must work:

=HYPERLINK("\\FIL-NW02-06\MPTTechTeamLeaders\8_Tech_Team_Scorecard\Reddy
Team Scorecards\2005_Define_Scorecard_Hixson.xls#'Score card - Tech
Group'!K12,"MyLink")

Arvi Laanemets

wrote in message
...
I tried this, here is the contents of the cell:

=HYPERLINK('\\FIL-NW02-06
\MPTTechTeamLeaders\8_Tech_Team_Scorecard\Reddy Team
Scorecards\[2005_Define_Scorecard_Hixson.xls]Scorecard -
Tech Group'!K12)

and I get the little hyperlink hand icon but when I click
nothing happens.

Wayne

-----Original Message-----
Check out the HYPERLINK function.
Example:
=HYPERLINK("[C:\Temp\MyFile.xls]Data!$C$2","Test")
will show the word 'Test' in the cell. When selected,
the hyperlink will
take you to the 'MYFILE' workbook, the 'Data' worksheet,
cell C2.
HTH,
Gary Brown

"Wayne" wrote in
message
...
I have a paste link cell in a spreadsheet, referring to
a
source cell in another spreadsheet and cell. Is there a
way in VBA to open that source spreadsheet and "jump"
to
the source cell?

Wayne


.


--

Dave Peterson